mikey Posted February 6, 2012 Share Posted February 6, 2012 I'm just curious to find where it stuffs the timer value that's supposed to simulate one disk rotation. Hi, Bryan There ... 1610 LDA #$D2 for timeout 1620 F1T1 BIT DRA write 1 byte 00 at DRQ 1630 BPL F1T1 1640 STY DATREG 1650 F1T2 BIT DRA another byte 00 1660 BPL F1T2 1670 STY DATREG 1680 STA T1024I start timer $d2*1024 cycles (1024T timer) gives 215040 usecs, that would be about 0,21 sec. At 288 rpm there's 4,8 rotation per second which gives one rotation time of 0,208 sec Sounds legit Correct me if I am wrong Quote Link to comment Share on other sites More sharing options...
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